[Gllug] OT: algorithm needed

[salsaman at xs4all.nl]

On Sun, August 10, 2008 22:49, Ben Whyte wrote:
>
>> Cant you do this by taking the total and dividing it by the max which
>> gives you the number of times that the max goes into the total, then
>> divide the total by this number which will give you equal number of
>> blocks.
>>
>> Wouldnt that give you what you want ?
>>
>> Ben
>
> Really must read what i type properly.  You need to round the total/max
> up to the next whole number before dividing total by it.
>
> Ben
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>

Yes I think that is along the right lines:

ceil (100/45) = 3;

100/3 = 33, remainder 1.

First read is 33+remainder = 34, next reads are 33.


I knew I was missing something obvious !


Thanks for your help.
Gabriel.


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