[Gllug] Historical question
steve at fractalus.com
Mon Aug 16 09:51:42 UTC 2004
* Jason (jason at jasonsgems.co.uk) wrote:
> > 128 k * 1024 byte/k * 8 bit/byte / 2400 bit/sec / 60 sec/min
> > == 7 min
> > which is about the right magnitude, but I think more like twice that
> > long? So 1200 bit /sec would mean half a meg on a tape?
> is this a 60min or 90 min tape (or the 15min tapes you used to get for the
> speccy etc)?
for this back-of-email calculation it doesn't matter, just figuring if
the bit-per-second rate it about right. From other emails it looks like
the lower figure of 1200 is good...
SteveC steve at fractalus.com http://www.fractalus.com/steve/
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