[Gllug] Arithmetic error in bash on 08 and 09?

[Liam Delahunty]

I've got a little script running as an hourly cron job. (Basically
I've found that Mailscanenr starts to have problems in the wee hours
and stop/start helps).

#!/bin/sh
previoushour=`date "+%H"`
previoushour=$((previoushour-1))
today=`date "+%b %d"`
then=$today" "$previoushour
killed=`grep "$then" /var/log/maillog | grep 'SpamAssassin timed out
and was killed'|wc -l`
if [ "$killed" -ge "1" ]; then
 echo "$then SpamAssassin timed out and was killed $killed"
 grep "$then" /var/log/maillog | grep 'SpamAssassin timed out and was killed'
 /etc/rc.d/init.d/MailScanner stop
 sleep 4
 /etc/rc.d/init.d/MailScanner status
 sleep 4
 echo "restart MailScanner"
 /etc/rc.d/init.d/MailScanner start
 /etc/rc.d/init.d/MailScanner status
fi

But I get errors at both 8 am and 9 am, presumably because of the arithmetic.

Here's the eight o'clock error.
/etc/cron.hourly/check_mailscanner_spam.sh: 08: value too great for
base (remainder of expression is "08")

Here's the nine o'clock error.

/etc/cron.hourly/check_mailscanner_spam.sh: 09: value too great for
base (remainder of expression is "09")

Why? Why not 01, 02, 03 etc... and naturally, any suggestions for
improving the script.

-- 
Kind regards, Liam Delahunty
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