[Nottingham] A numerical puzzle & "mathomatic"

[Camilo Mesias]

It doesn't need that much brute force because the equation is so
limited. The a+b+c bit appears twice and they are single digits. If n
is a+b+c we can figure n is between 0 and 27, and n^2 + n is a three
digit number. We have to start at n=10 to get a three digit result
(110) but those digits don't add up to 10...
n=11 (132)...
n=12 (156) bingo

just as well because my times tables run out there!