[Nottingham] A numerical puzzle & "mathomatic"

Camilo Mesias camilo at mesias.co.uk
Mon Jan 18 00:35:58 UTC 2010

It doesn't need that much brute force because the equation is so
limited. The a+b+c bit appears twice and they are single digits. If n
is a+b+c we can figure n is between 0 and 27, and n^2 + n is a three
digit number. We have to start at n=10 to get a three digit result
(110) but those digits don't add up to 10...
n=11 (132)...
n=12 (156) bingo

just as well because my times tables run out there!

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