[Phpwm] displaying images on screen

[alan dunn]

Thanks so far - I didn't get all the question correct! We agree about 
how to put the image to the page. The problem (I now understand) is that 
we want to show it as a pop-up within an existing page, so the header 
line is already set: content="text/html; "

What this does is cause the image to display as text.

thanks again, alan

BinaryKitten wrote:
> alan dunn wrote:
>   
>> This probably has an easy answer, but we haven't found it.
>>
>> We have an archive of jpeg images. We want to open one using GD library
>>
>> $im1 = imagecreatefrom jpeg($pathname.$filename);
>>
>>  rotate it:
>>
>> $im1 = imagerotate($im1,-90,0);           .... and display it on screen.
>>
>> How do we get to display the image which is now represented by resource 
>> $im1?
>> We know you can do it by saving the rotated image back to somewhere then 
>> displaying the saved image - but that's a lot of overhead just to show a 
>> temporarily rotated image.
>>
>> Any help much appreciated, thanks, Alan Dunn
>>
>>
>>   
>>     
> as you've created a jpeg resource, you will need to output the header 
> that you are ouputing a jpeg instead of the standard html.. to do this 
> use the following snippet:
>
> header("Content-type: image/jpeg");
>
> then call upon the imagejpeg function passing $im1 to it like so:
> imagejpeg($im1);
>
> you can also save to a file if you want, again using hte imagejpeg function
> imagejpeg($im1, "/path/filename.jpg")
>
> as well as choose the quality level you want to ouput
> imagejpeg($im1, null,(0-100))  // Output to screen @ quality level
> imagejpeg($im1, "/path/filename.jpg", (0-100))
> // Output to file @ quality level
>
> the default quality level is 75.
>
> Finally don't forget to call imagedestroy($im1) afterwards to clean up 
> the memory...
>
> Kat
>
>
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>
>   

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