[SC.LUG] Complex Factors Of Primes

[Frank Mitchell]

I'm surprised at you fellas:

The whole point is that "i" or "j" is the Square Root of Minus One.
Thus minus i squared equals Plus One. So:

(2+i)*(2-i) = 4+1 = 5

(3+2i)*(3-2i) = 9+4 =13

Quaternions have 3 different square roots of -1, called i, j, k, and they too 
have Complex Conjugates like Complex Numbers. The Imaginary Components i, j, k 
then gave us the idea of Vectors. Divide two Vectors and you get a Quaternion.

Faictz Ce Que Vouldras: Frank Mitchell