[sclug] c++ / g++ 3.3.2 question on using STL transforms

[Tim Sutton]

Hi

I am trying to use an STL transform to convert a string to uppercase. 
Previously I have used:

std::transform (myString.begin(),myString.end(), myString.begin(), toupper);

successfully. Now it seems things have changed, from what I can make out to 
manage issues with unicode upper to lower and lower to upper conversion. 
Unfortunately, from the few examples I could find, I am unable to get the  
toupper transform to work properly under g++ 3.3.2.

Can anyone help me out here?

Below is a mockup showing what I am trying to do - it segfaults on the 
transform line.

Many thanks

Tim


#ifdef HAVE_CONFIG_H
#include <config.h>
#endif

#include <iostream>
#include <stdlib.h>

#include <algorithm>
#include <cctype>

using namespace std;

//this struct is required for stl transform operations
//you used to not need it but now you do as described at:
//http://linux-rep.fnal.gov/software/gcc/onlinedocs/libstdc++/22_locale/
howto.html#7
//and
//
struct ToUpper
{
	ToUpper (std::locale const& l) : loc(l) {;}
	char operator() (char c)  { return std::toupper(c,loc); }
				private:
	std::locale const& loc;
};


int main(int argc, char *argv[])
{

    std::string myString;
//create an instance of the upper case struct as described at
//http://linux-rep.fnal.gov/software/gcc/onlinedocs/libstdc++/22_locale/
howto.html#7
	ToUpper      myUpperCaseStruct   ( std::locale("C") );
	//declare the key value
	myString=std::string("CRES African climate data");
	//convert it to upper case
	std::transform (myString.begin(),myString.end(), myString.begin(), 
myUpperCaseStruct);
	//show the result
	 cout << "Result is: " << myString << endl;

  
  return EXIT_SUCCESS;
}







-- 
Tim Sutton
BDWorld Middleware Programmer
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