[Gllug] print grep var in awk shell script?

[Liam Delahunty]

This little script is supposed to count how many times users get mail to 
their username account or log in.

It works okay but I'd like to display it better.

#!/bin/bash
for username in `ls -l /home/spool/mail/|grep site26| awk '{print $9 }'`
do
  echo $username
  grep $username /var/log/maillog | wc | awk '{print $1 " emails"}'
  grep 'login by user '.$username /var/log/maillog |wc | awk '{print $1 
" logins"}'
done

Currently the output is:
user001
22 emails
19 logins
user002
322 emails
298 logins

really I'd like

user001	22 emails
user001	19 logins
user002 322 emails
user002	298 logins

But I can't work out how to get the username var to display with the 
awk. Perhaps I should be using sed too?

As always, thanks in advance.

-- 
Kind regards, Liam Delahunty, Mega Products Ltd
12 Bury Place, London WC1A 2JL Fax: +44(0)871 224 7891
http://www.megaproducts.co.uk/ Internet Design & Development
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