[Gllug] print grep var in awk shell script?

[Stuart Sears]

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On Tuesday 02 Mar 2004 14:59, Liam Delahunty wrote:
> This little script is supposed to count how many times users get mail to
> their username account or log in.
>
> It works okay but I'd like to display it better.
>
> #!/bin/bash
> for username in `ls -l /home/spool/mail/|grep site26| awk '{print $9 }'`
> do
>   echo $username
this adds the carriage return. Use printf instead.
>   grep $username /var/log/maillog | wc | awk '{print $1 " emails"}'
>   grep 'login by user '.$username /var/log/maillog |wc | awk '{print $1
> " logins"}'
> done
how about
...
LOGINS=`grep $username /var/log/maillog | wc`
EMAILS=`grep 'login by user '.$username /var/log/maillog |wc`
printf "user: %0 \t logins: %1 \t emails: %2\n" $username $LOGINS $EMAILS
...

or, if you want output like
user	<tab>	logins <tab>	emails
username		150			300

you could use 
printf  "user \t	logins \t emails\n" (do this OUTSIDE the loop)
printf  "%0 \t  %1 \t  %2\n" $username $LOGINS $EMAILS

> But I can't work out how to get the username var to display with the
> awk. Perhaps I should be using sed too?
you could, but you don't have to...
>
> As always, thanks in advance.

- -- 
Stuart Sears RHCE/RHCX
Red Hat Certified Instructor
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