[Gllug] OT: algorithm needed
ben at whyte-systems.co.uk
Sun Aug 10 20:49:42 UTC 2008
> Cant you do this by taking the total and dividing it by the max which
> gives you the number of times that the max goes into the total, then
> divide the total by this number which will give you equal number of blocks.
> Wouldnt that give you what you want ?
Really must read what i type properly. You need to round the total/max
up to the next whole number before dividing total by it.
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