[Gllug] More Procmail

[Jackson, Harry]

> -----Original Message-----
> From: Paul Brazier [mailto:pbrazier at cosmos-uk.co.uk]
> Sent: 26 February 2002 10:33
> To: gllug at linux.co.uk
> Subject: RE: [Gllug] More Procmail
> 
> 
> > I would appreciate if someone could please enlighten me to 
> > this particularly
> > the left side of the equation.
> >                                              n
> >                    n   k-1               x   - 1
> >               w * Sum x    = w * ----------
> >                    k=1                    x - 1
> 
> This is the sum of a geometric progression
> 
> i.e.  w * (1 + x + x^2 + x^3 + x^4 + ... + x^(n-1))
> 
> they are just two algebraically equivalent ways of writing the same
> thing.
> 
> because (1 + x + x^2 + x^3 + x^4 + ... + x^(n-1)) * (x - 1) = x^n - 1
> 
> I guess it's just the way that scores are weighted if an expression
> apears multiple times.

Thank you for enlightening me. My maths is rusty in the extreme

w=1
x=3
n=4

Equation 1
1*(1+3+9+(3^(4-1) = 40

Equation 2
1*  (  ((3^4)-1) / 2  ) = 40

I know which one I find easier to understand.

Harry



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